5 times a whole number x is subtracted from 62 the result is less than 42 find the 3 lowest value of x
62-5x<40
62-40<5x
22<5x
4 2/5<x
X>4 2/5
Since is a whole number and -4 is too small and 9,10 and 11 are too big the answer will be 5, 6, and 7
Well, well, well, let's have some math fun, shall we? So, we have the equation 62 - 5x < 42. To find the three lowest values of x, we need to solve this inequality.
First, let's isolate x by subtracting 62 from both sides: -5x < 42 - 62, which simplifies to -5x < -20.
Now, divide both sides of the inequality by -5, but remember, when we divide an inequality by a negative number, we must flip the inequality sign. So, we have x > -20 / -5, or x > 4.
Since we are looking for the three lowest values of x, let's start with x = 5. Plug it back into the equation: 62 - 5(5) = 37, which is indeed less than 42.
Next, let's try x = 6. Plug it in: 62 - 5(6) = 32, which is also less than 42.
Lastly, let's give x = 7 a shot. Plug it in: 62 - 5(7) = 27, and that's still less than 42.
So, the three lowest values of x that satisfy the inequality are x = 5, x = 6, and x = 7. Ta-da!
na lie
e no truee
5x-62 less than 40
5x/5 less than 102/5
To find the three lowest values of x, we need to solve the given equation and determine the range of x that satisfies the condition.
Let's translate the problem into an equation:
62 - 5x < 42
Now, we can solve this inequality step by step:
Step 1: Subtract 62 from both sides of the inequality:
-5x < 42 - 62
Simplifying:
-5x < -20
Step 2: Divide both sides of the inequality by -5. Remember, when dividing by a negative number, the direction of the inequality sign must be flipped:
x > (-20) / -5
Simplifying:
x > 4
So, we have found that the value of x must be greater than 4. However, we are looking for the three lowest values of x.
The three lowest values of x that satisfy the given condition are:
1. x = 5
2. x = 6
3. x = 7
Checking each value:
For x = 5:
62 - 5(5) = 62 - 25 = 37 (which is less than 42)
For x = 6:
62 - 5(6) = 62 - 30 = 32 (which is less than 42)
For x = 7:
62 - 5(7) = 62 - 35 = 27 (which is less than 42)
Hence, the three lowest values of x that satisfy the given condition are 5, 6, and 7.
5 times a whole number x ... 5x
is subtracted from 62 ... 62-5x
now finish it off