Pressure at a point 5m below the free surface of water is
atmospheric pressure + density of water * g * 5
Answer
To calculate the pressure at a point below the free surface of water, we can use the equation for pressure in a fluid.
The pressure at any point in a fluid is given by:
P = P₀ + ρgh
Where:
P is the pressure at the desired point,
P₀ is the atmospheric pressure above the fluid (usually taken as 1 atm),
ρ is the density of the fluid,
g is the acceleration due to gravity, and
h is the depth of the point below the free surface.
In this case, we are given that the point is 5m below the free surface of water. The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is 9.8 m/s².
Plugging in these values into the equation, we get:
P = 1 atm + (1000 kg/m³)(9.8 m/s²)(5m)
Now, let's calculate the pressure at the given point using this equation:
P = 1 atm + (1000 kg/m³)(9.8 m/s²)(5m)
P = 1 atm + 49000 N/m²
P ≈ 49600 N/m²
Therefore, the pressure at a point 5m below the free surface of water is approximately 49600 Newtons per square meter (N/m²), which is also equivalent to 49.6 kilopascals (kPa).