A piece of copper weighing 250 is heated to 100 and then quickly transferred to a copper calorimeter of mass 15 containing 80 of liquid with an unknown specific heat capacity at a room temperature of 10.caluate the SHC of the liquid.SHC of copper is 40.please help
To calculate the specific heat capacity (SHC) of the liquid, we can use the principle of heat transfer. The equation for heat transfer is:
Q = m * c * ΔT
where Q represents the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
In this scenario, the heat lost by the copper will be equal to the heat gained by the liquid in the calorimeter.
First, let's calculate the heat lost by the copper:
Q_copper = m_copper * c_copper * ΔT_copper
m_copper = 250 g (given)
c_copper = 40 (specific heat capacity of copper)
ΔT_copper = (100°C - 10°C) = 90°C
Q_copper = 250g * 40 * 90°C
Next, let's calculate the heat gained by the liquid in the calorimeter:
Q_liquid = m_liquid * c_liquid * ΔT_liquid
m_liquid = 80g (given)
c_liquid = unknown specific heat capacity
ΔT_liquid = (100°C - 10°C) = 90°C
Q_liquid = 80g * c_liquid * 90°C
Since the heat lost by the copper is equal to the heat gained by the liquid, we can equate the two equations:
250g * 40 * 90°C = 80g * c_liquid * 90°C
To find c_liquid, we simply solve for it:
c_liquid = (250g * 40 * 90°C) / (80g * 90°C)
c_liquid = (250g * 40) / 80g
c_liquid = 125 / 2
c_liquid = 62.5
Therefore, the specific heat capacity of the liquid is 62.5.