Calculate the percentage of:
a) sulphur in sodium
b)carbon in calcium trioxocarbonate (iv)
c) oxygen in sodium tetraoxosulphate(iv)
First you need to use correct IUPAC names of sodium sulfate and calcium carbonate.
a. There is no Sulfur in sodium.
b. % C (by mass) in CaCO3 = 100*(atomic mass C/molar mass CaCO3)
c. % O (by mass) in Na2SO4 = 100*(4*atomic mass O/molar mass Na2SO4)
% something in anything = 100*(mass of the something/total mass of the anything). For example, we have a mixture of apples and oranges that has a mass of 10 grams. The apples are 2 grams and the oranges are 8 grams.
% apples = 100*(2/10) = 20%
% oranges = 100*(8/10) = 80%
I'll bet if I gave you the apples and oranges problem you would work it without hesitation. But make the same problem with C in CaCO3 and you need help. It's the same problem. In apples it mass apples/total mass and all of that times 100. In C in CaCO3 it's mass C/total mass and all of that tims 100. Don't get sidetracked by chemical formulae. It's all just math.
solutionto d question
solution to the problem
To calculate the percentage of an element in a compound, you need to divide the mass of the element by the molar mass of the compound and then multiply by 100.
Let's calculate the percentage of each element in the given compounds:
a) Sulphur in Sodium:
Sodium (Na) does not contain sulphur (S). Therefore, the percentage of sulphur in sodium is 0%.
b) Carbon in Calcium Trioxocarbonate (IV):
The compound formula for calcium trioxocarbonate (IV) is CaCO3. To find the percentage of carbon, we need to calculate the molar mass of the compound:
- Molar mass of Ca = 40.08 g/mol
- Molar mass of C = 12.01 g/mol
- Molar mass of O = 16.00 g/mol
Now, we calculate the molar mass of the entire compound:
molar mass of CaCO3 = (mass of Ca) + (mass of C) + 3 x (mass of O)
= (40.08 g/mol) + (12.01 g/mol) + 3 x (16.00 g/mol)
= 100.09 g/mol
The percentage of carbon (C) in calcium trioxocarbonate (IV) is calculated as follows:
% of C = (mass of C / molar mass of CaCO3) x 100
= (12.01 g/mol / 100.09 g/mol) x 100
≈ 11.998%
Therefore, the percentage of carbon in calcium trioxocarbonate (IV) is approximately 11.998%.
c) Oxygen in Sodium Tetraoxosulphate (IV):
The compound formula for sodium tetraoxosulphate (IV) is Na2SO4. To find the percentage of oxygen, we need to calculate the molar mass of the compound:
- Molar mass of Na = 22.99 g/mol
- Molar mass of S = 32.06 g/mol
- Molar mass of O = 16.00 g/mol
Now, we calculate the molar mass of the entire compound:
molar mass of Na2SO4 = (2 x (mass of Na)) + (mass of S) + 4 x (mass of O)
= 2 x (22.99 g/mol) + (32.06 g/mol) + 4 x (16.00 g/mol)
= 142.04 g/mol
The percentage of oxygen (O) in sodium tetraoxosulphate (IV) is calculated as follows:
% of O = (mass of O / molar mass of Na2SO4) x 100
= (4 x (16.00 g/mol) / 142.04 g/mol) x 100
≈ 44.78%
Therefore, the percentage of oxygen in sodium tetraoxosulphate (IV) is approximately 44.78%.