The car was initially traveling at 15 m / s. The car slows down with an acceleration of -4.5 m / s² for 2 seconds. After these two seconds, what would be the final speed of the car?
keep in mind what acceleration is.
The car loses velocity at a rate of 4.5 m/s every second
So, after 2 seconds, it will have lost 9 m/s
15-9 = 6
To calculate the final speed of the car, we can use the formula:
final speed (v) = initial speed (u) + (acceleration (a) * time (t))
Given:
Initial speed (u) = 15 m/s
Acceleration (a) = -4.5 m/s²
Time (t) = 2 seconds
Plugging these values into the formula:
v = 15 m/s + (-4.5 m/s² * 2 s)
First, multiply the acceleration by the time:
v = 15 m/s + (-9 m/s)
To add the two velocities, we need to consider their directions. In this case, the initial speed (u) is positive and the acceleration (a) is negative. So, when we subtract 9 m/s from 15 m/s, the velocity will decrease.
v = 15 m/s - 9 m/s
v = 6 m/s
Therefore, the final speed of the car after 2 seconds of deceleration would be 6 m/s.
To determine the final speed of the car, we can use the equation of motion:
v = u + at
Where:
v = final velocity (unknown)
u = initial velocity = 15 m/s
a = acceleration = -4.5 m/s²
t = time = 2 seconds
Plug in the given values:
v = 15 m/s + (-4.5 m/s²)(2 s)
First, calculate the acceleration multiplied by time: -4.5 m/s² * 2 s = -9 m/s
Then, calculate the final velocity:
v = 15 m/s - 9 m/s = 6 m/s
Therefore, after two seconds, the final speed of the car would be 6 m/s.