If ln a=2, ln b=3, and ln c=5, evaluate the following:
a) ln(a^1/b^1c^-1)=
b)ln sqrt b^1c^1a^-4=
c) ln(a^3b^-1)/ln(bc)^-1=
d) (ln c^3)(ln a/b^-4)^-2=
huh? Just plug and chug. This is just Algebra II
(a) ln(2^1/3^1*5^-1) = ln 10/3 = 1.20
do the rest in like wise.