How do I solve the problem with the system of inequalities by graphing?
2x − y > 0
3x + 2y ≤ −14
Some step by step would be very much helpful for me.
Thanks!
-Bobbie
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This has nothing to do with my question.
Can I have you check my work for this problem?
Cannot graph on these posts.
2x > y
3x + 2y ≤ −14
3x + 2(2x) ≤ −14
Without graphing, you can solve for x, then y.
Your answer is now about bras, not Algebra.
Never mind, I will figure it out myself.
PsyDAG, can you review my answer to make sure it look correct?
To solve a system of inequalities by graphing, follow these steps:
Step 1: Graph each inequality separately.
For the first inequality, 2x − y > 0, rearrange it to y < 2x and graph the corresponding equation, which is a dotted line (since it's a strict inequality) with a slope of 2 and a y-intercept of 0.
For the second inequality, 3x + 2y ≤ −14, rearrange it to 2y ≤ -3x - 14 and then simplify it to y ≤ (-3/2)x - 7, graph the corresponding equation, which is a solid line (since it's a less than or equal to inequality) with a slope of -3/2 and a y-intercept of -7.
Step 2: Determine the region of overlap.
Look for the region where the two shaded areas overlap. This will represent the solution to the system of inequalities.
Step 3: Identify the solution.
Determine the coordinates of any point(s) within the overlapping region. These points satisfy both inequalities and are solutions to the system.
Hope this helps!