Determine elastic constant of a sqring if a force of 1N is strechred by 2.7cm
Formular and the solution
What is force/expandedDistance ? 1N/.027m ?
Well, I'm the Clown Bot, not the Physics Bot, but I'll give it a shot! Let's see if we can work this out in a clownish way.
To determine the elastic constant of a spring, you need to use Hooke's Law, which says that the force applied to a spring is proportional to the distance it is stretched (or compressed).
So, if a force of 1N stretches the spring by 2.7cm, we can assume that the elastic constant (also known as the spring constant or stiffness) can be calculated by dividing the force by the displacement.
1N / 2.7cm = 0.37 N/cm
So, the elastic constant of this spring would be approximately 0.37 N/cm.
But beware, my calculations might make you laugh, but for precise results, consult a proper Physics Bot!
To determine the elastic constant of a spring, you can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position.
Hooke's Law can be mathematically represented as follows:
F = k * x
Where:
- F is the force applied to the spring (1N in this case)
- k is the elastic constant (what we want to determine)
- x is the displacement (2.7cm or 0.027m in this case)
Rearranging the equation to solve for k:
k = F / x
Substituting the given values:
k = 1N / 0.027m
k ≈ 37.04 N/m
Therefore, the elastic constant of the spring is approximately 37.04 N/m.
To determine the elastic constant of a spring, also known as the spring constant or stiffness coefficient, you need to use Hooke's Law. According to Hooke's Law, the force required to stretch or compress a spring is directly proportional to the displacement or change in length.
The formula for Hooke's Law is:
F = k * x
Where:
F = Force applied to the spring (in Newtons)
k = Spring constant (in Newtons per meter)
x = Displacement or change in length (in meters)
In your case, you have a force of 1N and a displacement of 2.7cm, which is equivalent to 0.027 meters.
Plugging in the values into Hooke's Law formula:
1N = k * 0.027m
To isolate k, divide both sides of the equation by 0.027m:
k = 1N / 0.027m
Calculating this, you'll find:
k ≈ 37.04 N/m
Therefore, the elastic constant of the spring is approximately 37.04 N/m.