If the initial velocity is 18 m/s, then what is the velocity at time 22.5 s? acceleration is -2(m/s^2)
v = 18 - 2t
so plug in t=22.5
i got -27 but it is telling me its wrong
dunno. -27 is the answer from what you have said.
To find the velocity at a specific time, you can use the equation of motion that relates velocity, time, and acceleration. The equation is:
velocity = initial velocity + (acceleration × time)
In this case, the initial velocity is given as 18 m/s, the acceleration is -2 m/s^2, and the time is 22.5 s. Plugging these values into the equation, we can calculate the velocity:
velocity = 18 m/s + (-2 m/s^2) × 22.5 s
Step 1: Multiply the acceleration by the time,
velocity = 18 m/s + (-2 m/s^2 × 22.5 s)
Solving this multiplication gives us
velocity = 18 m/s + (-45 m/s)
Step 2: Add the initial velocity to the result from the previous step,
velocity = 18 m/s - 45 m/s
Step 3: Subtract the two velocities to find the final velocity,
velocity = -27 m/s
Therefore, the velocity at 22.5 seconds is -27 m/s.