A ball is dropped from the top of a building. If it takes 3.00 s for the ball to hit the street below, how high is the building?
44.1 m was the correct answer
Well, height is a sensitive topic for buildings. Some buildings are tall, some are short, and some buildings have serious height complexes. But don't worry, I'm here to help you with the math!
Now, if we consider the physics of the situation, we can use the formula for the height of an object in free fall. The formula is h = (1/2)gt^2, where h represents the height, g is the gravitational acceleration (which is approximately 9.8 m/s^2 on Earth), and t is the time it takes for the object to fall.
In this case, we know t = 3.00 s. So, if we plug that into the formula, we get h = (1/2)(9.8 m/s^2)(3.00 s)^2. Crunching the numbers, we find that the height of the building is approximately 44.1 meters.
So, it seems like the building you're talking about is about 44.1 meters tall. But remember, buildings have feelings too, so be kind and never make fun of a building's height!
To find the height of the building, we can use the equation of motion for free fall:
h = (1/2)gt^2
where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time it takes for the ball to hit the ground.
Plugging in the given values:
h = (1/2) * 9.8 m/s^2 * (3.00 s)^2
h = (1/2) * 9.8 m/s^2 * 9.00 s^2
h = 44.1 m
Therefore, the height of the building is 44.1 meters.
To determine the height of the building, we can use the equation of motion for a freely falling object. This equation relates the height (h) of the object to the time it takes to fall (t) and the acceleration due to gravity (g), which is approximately 9.8 m/s^2 near the Earth's surface.
The equation is: h = 0.5 * g * t^2
In this case, we know that the time it takes for the ball to hit the street below is 3.00 seconds. Plugging this value into the equation, we can solve for h:
h = 0.5 * (9.8 m/s^2) * (3.00 s)^2
h = 0.5 * 9.8 m/s^2 * 9.00 s^2
h = 44.1 m
Therefore, the height of the building is approximately 44.1 meters.
vf = 0
t = 3.00
a = -g
y = ?
y = vft - 1/2at^2
y = 0 - 1/2(-9.80)(3.00)^2
y = 4.40(9.00)
y = 39.6 m
the building is 39.6 m high