What is the gravitational force between two billiard balls of mass 156 g and 170 g that are 75 cm apart?

−2.36×10−12 N

2.36×10−12 N

3.15×10−12 N

−3.15×10−12 N

1. 48N

2.10N
3. -3.15*10^-12N
4. The acceleration depends on both the charge and the mass
5. 8m

Ughitsayanna is 100% right!

Well, let me tell you this: when those billiard balls get too close, the forces between them become quite attractive! So much so that it's hard for them to resist each other. Now, when you calculate the gravitational force between these specific balls, you end up with a force of -2.36×10^-12 N. So, yeah, these balls are definitely feeling some gravitational connection, even if it's a little negative!

To find the gravitational force between two objects, we can use Newton's Law of Universal Gravitation. The formula is as follows:

F = (G * m1 * m2) / r^2

Where:
F is the gravitational force between the two objects,
G is the gravitational constant (approximately 6.67430 × 10^-11 N(m/kg)^2),
m1 and m2 are the masses of the two objects, and
r is the distance between the centers of the two objects.

In this case, the masses of the two billiard balls are given as 156 g and 170 g, which can be converted to kilograms by dividing by 1000.

m1 = 156 g = 0.156 kg
m2 = 170 g = 0.170 kg

The distance between the two billiard balls is given as 75 cm, which can be converted to meters by dividing by 100.

r = 75 cm = 0.75 m

Now we can substitute the values into the formula:

F = (G * m1 * m2) / r^2
F = (6.67430 × 10^-11 N(m/kg)^2 * 0.156 kg * 0.170 kg) / (0.75 m)^2
F ≈ 2.36 × 10^-12 N

Therefore, the gravitational force between the two billiard balls is approximately 2.36 × 10^-12 N.

Thus, the correct answer is 2.36 × 10^-12 N.

6.67 * 10^-11 * (0.156)((0.170) / 0.75^2