Two charges q1 and q2exert a 90 N electrostatic force onto each other when they are 1 m apart. They are moved further away to a distance of 3 m. What will the new electrostatic force be?
30 N
810 N
270 N
10 N
Amy pushes a 10 kg to the left with 20 N of force. If the force of friction is 5 N of force, calculate the acceleration of the box and its direction.
To find the new electrostatic force between the charges q1 and q2 when they are 3 m apart, we can use Coulomb's Law. Coulomb's Law states that the electrostatic force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The formula for Coulomb's Law is:
F = k * (q1 * q2) / r^2
where F is the electrostatic force, k is the electrostatic constant (k = 8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges in coulombs, and r is the distance between the charges in meters.
Given that the electrostatic force between the charges when they are 1 m apart is 90 N, we can plug in the values into the equation and solve for k:
90 = k * (q1 * q2) / 1^2
Rearranging the equation, we have:
k = 90 / (q1 * q2)
Now, we need to find the value of k. Plugging the values into the equation:
k = 90 / (q1 * q2)
Next, we can use the value of k to find the new electrostatic force when the charges are 3 m apart:
F = k * (q1 * q2) / 3^2
Simplifying the equation gives us:
F = (90 / (q1 * q2)) * (q1 * q2) / 9
The (q1 * q2) terms in the numerator and denominator cancel out, leaving us with:
F = 10 N
Therefore, the new electrostatic force between the charges q1 and q2 when they are 3 m apart will be 10 N.