Find the relationship between x and y when x is partly constant and partly varies with y
When y = 3, x= 7 and when y = 6, x= 9
Hm, what is the question here? I'm good with this stuff but I need to know more if you want help.
well, assume linear maybe
x = m y + b it gives them that way
7 = 3 m + b
9 = 6 m + b
===============
14 = 6 m + 2 b
9 = 6 m + b
--------------------subtract
5 = b
then
9 = 6 m + 5
6 m = 4
m = 2/3
so
x = (2/3) y + 5
3 x = 2 y + 15
x = my+b
using the data points, you have
3m+b = 7
6m+b = 9
so solve for m and b
To find the relationship between x and y when x is partly constant and partly varies with y, we need to analyze the given information.
We are given two data points:
1) When y = 3, x = 7
2) When y = 6, x = 9
From these data points, we can observe that when y increases from 3 to 6, x increases from 7 to 9.
Let's calculate the change in x (denoted by Δx) and the change in y (denoted by Δy):
Δx = 9 - 7 = 2
Δy = 6 - 3 = 3
Now, to determine how x varies with y, we can calculate the ratio of the change in x to the change in y:
Δx/Δy = 2/3
This ratio indicates that for every increase of 3 in y, x increases by 2.
With this information, we can conclude that when y is partly constant and partly varies with y, the relationship between x and y can be expressed using the equation:
x = 7 + (2/3)(y - 3)
In this equation, 7 represents the constant part of x, and (2/3)(y - 3) represents the variable part of x that depends on the change in y.
Therefore, the relationship between x and y, when x is partly constant and partly varies with y, can be represented by the equation x = 7 + (2/3)(y - 3).