What is the sodium ion concentration in 100.0 mL of 0.500 M sodium chloride
Sodium chloride is NaCl. That formula tells you there is 1 Na ion to 1 NaCl molecule; therefore 0.5 M NaCl will have 0.5 M Na ions and 0.5 M Cl ions.
To find the sodium ion concentration in a solution of sodium chloride, we need to understand that each formula unit of sodium chloride (NaCl) dissociates into one sodium ion (Na+) and one chloride ion (Cl-) when it dissolves in water.
Given that the solution is 0.500 M in sodium chloride, this means that there are 0.500 moles of NaCl dissolved in 1 liter of solution (1 L = 1000 mL).
To find the concentration in a specific volume, we use the formula:
Concentration (M) = moles of solute / volume of solution (in liters)
In this case, we have 0.500 moles of NaCl dissolved in 1 L of solution. We want to find the sodium ion concentration in 100.0 mL of this solution.
First, we convert the volume of the solution to liters:
100.0 mL = 100.0 mL * (1 L / 1000 mL) = 0.100 L
Now we can use the formula to find the concentration of sodium ions:
Concentration of Na+ (M) = moles of Na+ / volume of solution (in liters)
Since each formula unit of NaCl dissociates into one Na+ ion, the concentration of Na+ is equal to the concentration of NaCl. Therefore, the sodium ion concentration in 100.0 mL of the 0.500 M sodium chloride solution is also 0.500 M.