Write the first five terms of the sequence whose general term,a n , is given a a n=7n-4
a(n) = 7n - 4
a(1) = 7(1) - 4 = 7-4 = 3
a(2) = 7(2) - 4 = 14-4 = 10
...
a(5) = .....
So the first 5 terms are: 3, 10, ....
Assighment
Find the 5 terms of the sequence whose general term is given by
1.an=2n+1
To find the first five terms of the sequence with the general term a_n = 7n - 4, we can substitute different values of n into the formula.
First, let's find the value of a_1:
a_1 = 7(1) - 4 = 3
The first term of the sequence is 3.
Now, let's find the value of a_2:
a_2 = 7(2) - 4 = 10
The second term of the sequence is 10.
Next, let's find the value of a_3:
a_3 = 7(3) - 4 = 17
The third term of the sequence is 17.
Moving on, let's find the value of a_4:
a_4 = 7(4) - 4 = 24
The fourth term of the sequence is 24.
Finally, let's find the value of a_5:
a_5 = 7(5) - 4 = 31
The fifth term of the sequence is 31.
Therefore, the first five terms of the sequence with the general term a_n = 7n - 4 are 3, 10, 17, 24, and 31.