A net force of 0.7 N is applied on a body. What happens to the acceleration of the body in a second trial if half of the net force is applied?
The acceleration is half of its original value.
The acceleration remains the same.
The acceleration is double its original value.
The acceleration is the square of its original value.
I'm not very sure please explain if u can :\
F = ma
the mass does not change, so
1/2 the force means 1/2 the acceleration
Ok Mr.oobleck!
Oobleck is correct
Sure! To answer this question, we need to understand the relationship between net force and acceleration.
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force applied to it. Mathematically, this can be represented by the equation:
F = m * a
where F is the net force, m is the mass of the object, and a is the acceleration.
In this case, we are told that a net force of 0.7 N is applied to the body. Now, let's consider the second trial where only half of the net force is applied. This means the net force in the second trial would be 0.7 N / 2 = 0.35 N.
Since the mass of the body remains constant, the equation becomes:
0.35 N = m * a2
Comparing this with the original equation, we can see that the only difference is in the net force, while the mass remains the same. Therefore, we can conclude that the acceleration in the second trial would be half of its original value.
So, the correct answer is: The acceleration is half of its original value.