Which equation in slope-intercept form represents a line that passes through the point (5,−1) and is parallel to the line y=2x−7?
y=2x−11
y=−9x−7
y=2x−9
y=−12x−7
y=−11x−7
B?
math is a waste of time
ure mom
(5, -1)
Y = mx+b
-1 = 2*5+b
b = -11.
Y = 2x-11.
not the real ms sue but good try
To find the equation of a line that is parallel to a given line and passes through a given point, we can use the fact that parallel lines have the same slope.
First, let's find the slope of the given line y = 2x - 7. The slope-intercept form of a line is y = mx + b, where m is the slope. In this case, the slope is 2.
Since the new line is parallel to the given line, it will also have a slope of 2. Now we can use the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.
Substituting the values of the given point (5, -1) and the slope (2) into the point-slope form, we get:
y - (-1) = 2(x - 5)
y + 1 = 2(x - 5)
Now, let's simplify the equation:
y + 1 = 2x - 10
Finally, let's rewrite the equation in slope-intercept form (y = mx + b) by isolating y:
y = 2x - 10 - 1
y = 2x - 11
Therefore, the equation in slope-intercept form that represents a line passing through the point (5, -1) and parallel to the line y = 2x - 7 is y = 2x - 11.
12
parallel lines have the same slope...so the x-coefficients have to be the same
use the given point to test the two that have the right slope (x-coefficient)
just to clarify, the slope must be 2. Now you have apoint and a slope, so start with the point-slope form of the line:
y+1 = 2(x-5)
Now see which choice matches that when rearranged to slope-intercept form.