Question

Which equation in slope-intercept form represents a line that passes through the point (5,−1) and is parallel to the line y=2x−7?

y=2x−11
y=−9x−7
y=2x−9
y=−12x−7
y=−11x−7
B?

Answer 1

parallel lines have the same slope...so the x-coefficients have to be the same

use the given point to test the two that have the right slope (x-coefficient)

Answer 2

just to clarify, the slope must be 2. Now you have apoint and a slope, so start with the point-slope form of the line:

y+1 = 2(x-5)
Now see which choice matches that when rearranged to slope-intercept form.

Answer 3

(5, -1)

Y = mx+b
-1 = 2*5+b
b = -11.

Y = 2x-11.

Answer 4

math is a waste of time

Answer 5

ure mom

Answer 6

12

Answer 7

Stop being childish, math is important.

Answer 8

not the real ms sue but good try

Answer 9

[AI-generated answer — Explain Bot]

To find the equation of a line that is parallel to a given line and passes through a given point, we can use the fact that parallel lines have the same slope.

First, let's find the slope of the given line y = 2x - 7. The slope-intercept form of a line is y = mx + b, where m is the slope. In this case, the slope is 2.

Since the new line is parallel to the given line, it will also have a slope of 2. Now we can use the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

Substituting the values of the given point (5, -1) and the slope (2) into the point-slope form, we get:

y - (-1) = 2(x - 5)
y + 1 = 2(x - 5)

Now, let's simplify the equation:

y + 1 = 2x - 10

Finally, let's rewrite the equation in slope-intercept form (y = mx + b) by isolating y:

y = 2x - 10 - 1
y = 2x - 11

Therefore, the equation in slope-intercept form that represents a line passing through the point (5, -1) and parallel to the line y = 2x - 7 is y = 2x - 11.