The sum of three consecutive numbers is 108.
If the middle number is x, then
x-1 + x + x+1 = 108
3x = 108
...
let the numbers be x
x+x+x=108
3x=108
=108 divided by3
=36
therefore x = 36
To find the three consecutive numbers, we will use algebraic equations. Let's assume the first number is x.
The second number will be the next consecutive number, which is x + 1.
The third number will be the consecutive number after the second number, which is (x + 1) + 1, or x + 2.
Now we can set up an equation to solve for x:
x + (x + 1) + (x + 2) = 108
Simplifying the equation:
3x + 3 = 108
Subtracting 3 from both sides:
3x = 105
Dividing both sides by 3:
x = 35
So, the first number is 35, the second number is 36, and the third number is 37.