The secondary coil consists of 20 loops and has an output voltage of 80 V. If the primary coil had 100 loops, what was the voltage across the primary coil?
400 V
80 V
25 V
20 V
400 V Thank you!
100/20 * 80 = ___
To find the voltage across the primary coil, we can use the formula for transformer voltage ratio: Vp/Vs = Np/Ns, where Vp is the voltage across the primary coil, Vs is the voltage across the secondary coil, Np is the number of loops in the primary coil, and Ns is the number of loops in the secondary coil.
Given that the secondary coil has 20 loops and an output voltage of 80 V, and the primary coil has 100 loops, we can substitute these values into the formula:
Vp/80 = 100/20
Cross-multiplying, we get:
Vp = (100/20) * 80
Simplifying, we have:
Vp = 5 * 80
Therefore, the voltage across the primary coil is 400 V.
So, the correct answer is 400 V.
To find the voltage across the primary coil, you can use the formula for voltage in a transformer:
V₁/V₂ = N₁/N₂
Where:
V₁ = voltage across the primary coil
V₂ = voltage across the secondary coil
N₁ = number of loops in the primary coil
N₂ = number of loops in the secondary coil
In this case, V₂ (voltage across the secondary coil) is given as 80 V, and N₂ (number of loops in the secondary coil) is given as 20. N₁ (number of loops in the primary coil) is given as 100, and we need to solve for V₁.
Substituting the given values into the formula, we have:
V₁/80 = 100/20
To solve for V₁, we can cross-multiply:
V₁ = 80 * (100/20) = 400 V
Therefore, the voltage across the primary coil is 400 V.
The correct answer is 400 V.