Based on the titration results, what is the concentration of the sulfuric acid?
Volume of πΎππ» 36 mL
Concentration of πΎππ» 0.16 M
Volume of π»2ππ4 12 mL
H2SO4 + 2KOH ==> K2SO4 + 2H2O
mols KOH = M x L = ?
Look at the equation to see that mols H2SO4 = 1/2 mols KOH
Then M H2SO4 = mols/L
Post your work if you get stuck.
Hsb
To find the concentration of sulfuric acid (H2SO4) based on the titration results, you can use the principle of stoichiometry. In a neutralization reaction between potassium hydroxide (KOH) and sulfuric acid, the mole ratio is 1:2. This means that for every mole of KOH, two moles of H2SO4 react.
Let's start by calculating the number of moles of KOH:
Moles of KOH = Volume of KOH (in liters) Γ Concentration of KOH (in mol/L)
Given that the volume of KOH is 36 mL and the concentration is 0.16 M, we need to convert the volume to liters:
Volume of KOH = 36 mL Γ (1 L/1000 mL) = 0.036 L
Now we can calculate the moles of KOH:
Moles of KOH = 0.036 L Γ 0.16 mol/L = 0.00576 mol
Since the mole ratio between KOH and H2SO4 is 1:2, the moles of H2SO4 will be twice the moles of KOH:
Moles of H2SO4 = 2 Γ Moles of KOH
Moles of H2SO4 = 2 Γ 0.00576 mol = 0.01152 mol
To find the concentration of the sulfuric acid, divide the moles of H2SO4 by the volume of H2SO4 in liters:
Concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4 (in liters)
Given that the volume of H2SO4 is 12 mL, which is equivalent to 0.012 L:
Concentration of H2SO4 = 0.01152 mol / 0.012 L = 0.96 M
Therefore, the concentration of the sulfuric acid is 0.96 M based on the titration results.