The cost, C, in dollars of producing n yearbooks is represented by the equation
C =1000+5n
Last year it cost $1375 for all the books. What is the highest number of books they can produce this year so they don’t spend as much money? Show your work
1000 + 5 n < 1375
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To find the highest number of books they can produce this year without spending as much money, we need to solve the equation C = 1000 + 5n for n.
Given that it cost $1375 for all the books last year, we can set C equal to 1375 and solve for n:
1375 = 1000 + 5n
To isolate the variable n, we can subtract 1000 from both sides of the equation:
1375 - 1000 = 5n
375 = 5n
Next, divide both sides of the equation by 5:
375 / 5 = n
75 = n
Therefore, last year they produced 75 yearbooks.
To find the highest number of books they can produce this year without spending as much money, we can substitute n = 75 into the equation C = 1000 + 5n:
C = 1000 + 5(75)
C = 1000 + 375
C = 1375
By substituting n = 75, we find that the cost of producing 75 yearbooks this year is also $1375.
To answer the question, the highest number of books they can produce this year without spending as much money is 75.