is this correct?
factor completely: 9x^2-4
my answer: x is approx. +/- ((sqrt (14)/(3))
nope
(3x-2)(3x+2)
nope
(3x-2)(3x+2)
To factor completely, we need to find the expression in factored form.
In this case, we have 9x^2 - 4. To factor this polynomial, we can use the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b).
In our equation, a is 3x and b is 2. Therefore, we can rewrite our expression as follows:
9x^2 - 4 = (3x)^2 - 2^2
= (3x + 2)(3x - 2).
Thus, the correct factored form of 9x^2 - 4 is (3x + 2)(3x - 2).