H₃PO₄(aq) and KOH(aq) → K₃PO₄(aq) + H₂0(ℓ) Which of the following are spectator ions that wouldn't be written in the net ionic equation?
PO₄³⁺
K⁺
OH-
H⁺
The net ionic equation is H^+(aq) + OH^-(aq) ==> H2O(l)
To determine the spectator ions in the reaction, we need to first write the complete ionic equation by breaking down all the reactants and products into their respective ions.
The given equation is:
H₃PO₄(aq) + KOH(aq) → K₃PO₄(aq) + H₂O(ℓ)
Let's write the complete ionic equation by breaking down the soluble compounds into their respective ions:
H₃PO₄(aq) → 3H⁺(aq) + PO₄³⁻(aq)
KOH(aq) → K⁺(aq) + OH⁻(aq)
K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq)
H₂O(ℓ) → H₂O(ℓ)
Now we can identify the spectator ions by comparing the ions present on both sides of the arrow in the complete ionic equation. The spectator ions are the ones that appear on both sides and remain unchanged.
In this case, the spectator ions are:
K⁺ and PO₄³⁻
H⁺ and OH⁻ are not spectator ions because they are involved in the chemical reaction and are consumed to form water (H₂O).
Therefore, the spectator ions that wouldn't be written in the net ionic equation are K⁺ and PO₄³⁻.