Can someone help me with this question?
A spring has a spring constant of 300 N/m. Find the magnitude of the force needed to compress the spring by 0.03 m. Hint: Use Hooke’s law. The restoring force of an ideal spring is F=-kx, where k is the spring constant and x is the displacement of the spring from its original length.
f=kx=300*.03= ???
Sure! I can help you with that.
The formula you provided, F = -kx, is Hooke's law, which relates the force exerted by a spring to its displacement. In this case, you are given the spring constant (k = 300 N/m) and the displacement of the spring (x = 0.03 m), and you need to find the magnitude of the force (F).
To find the force, you can simply substitute the given values into the Hooke's law equation. Since the displacement is in the negative direction (compressed spring), the force magnitude will be positive.
F = -(300 N/m)(0.03 m)
Now, we can calculate the force:
F = -(9 N/m)(0.03 m)
F = -9 N
Since we want the magnitude, we take the absolute value of the result:
|F| = 9 N
Therefore, the magnitude of the force needed to compress the spring by 0.03 m is 9 N.
Sure! To find the magnitude of the force needed to compress the spring by 0.03 m, we can use Hooke's Law equation, which states that the restoring force of an ideal spring is given by F = -kx, where F is the force, k is the spring constant, and x is the displacement from the original length.
In this case, we are given that the spring constant is 300 N/m (newton per meter) and the displacement is 0.03 m. By substituting these values into Hooke's Law equation, we can find the magnitude of the force.
F = -(300 N/m) * 0.03 m
= -9 N
The negative sign indicates that the force exerted by the spring is in the opposite direction of the displacement. So, the magnitude of the force needed to compress the spring by 0.03 m is 9 N.