A ball of mass 0.3kg moving at a velocity of 20ms is suddenly hit by a force of 5N for a time of 0.03secs.find its new velocity of motion.
force direction?
I bet you were told that Force is a vector.
It has magnitude AND direction.
Once you get that straightened out
net force on system = Force = rate of change of momentum of system
so if a system has a certain momentum
and a force acts on it for n seconds
the change in its momentum will be the force times the time
F t = change in m V
To find the new velocity of the ball, we can use Newton's second law of motion, which states that the force acting on an object is equal to the product of its mass and acceleration (F = ma).
1. First, let's find the acceleration of the ball using the equation F = ma.
F = 5 N (given force)
m = 0.3 kg (given mass)
a = F/m = 5 N / 0.3 kg = 16.67 m/s^2
2. Now, we can calculate the change in velocity of the ball using the equation v = u + at, where:
v = final velocity
u = initial velocity (given as 20 m/s)
a = acceleration (found in step 1)
t = time (given as 0.03 s)
Plugging in the values:
v = 20 m/s + (16.67 m/s^2) * (0.03 s)
v = 20 m/s + 0.5 m/s
v = 20.5 m/s
Therefore, the new velocity of the ball after being hit by a force of 5 N for 0.03 seconds is 20.5 m/s.
To find the new velocity of the ball, we can use the formula:
Force (F) = mass (m) × change in velocity (Δv) / time (t)
First, let's rearrange the formula to solve for Δv:
Δv = (F × t) / m
Now we can substitute the given values:
mass (m) = 0.3 kg
Force (F) = 5 N
time (t) = 0.03 s
Δv = (5 N × 0.03 s) / 0.3 kg
Simplifying the equation:
Δv = 0.15 m/s
Finally, to find the new velocity, we need to add the change in velocity to the initial velocity of the ball:
New velocity = Initial velocity + Δv
Given:
Initial velocity = 20 m/s
Δv = 0.15 m/s
New velocity = 20 m/s + 0.15 m/s
New velocity = 20.15 m/s
Therefore, the new velocity of the ball after being hit by the force is 20.15 m/s.