When 'k' is added to the expression y² - 12, the expression becomes (y+p)². Find the values of 'p' and 'k'.
I assume you meant
y^2 - 12y + k
Recall that (y+p)^2 = y^2 + 2py + p^2
So, you have 2py = -12y, so p = -6
Now what is p^2 = k?
Pls can you solve it into details
No
No understanding for the answer
To find the values of 'p' and 'k', we need to compare the given expression, y² - 12, with the expression (y + p)² after 'k' is added.
Comparing the two expressions, we can see that the term being squared is y. Therefore, we have:
(y + p)² = y² - 12
Expanding the expression (y + p)² gives us:
y² + 2yp + p² = y² - 12
Now, we can compare the coefficients of y² on both sides of the equation. The coefficient of y² on the left side is 1, and there is no y² term on the right side, so we have:
1 = 0
Since this equation is not true, it means that there are no values of 'p' and 'k' that satisfy the given condition.