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another of these?
where do you get stuck?
-3(r-4) ≥ 0
where do you get stuck?
Can you solve
3x ≥ 0 ??
If so, then find x, and then let x = r-4 and then find r.
-3(5-4) = -3 which is not ≥4
when you multiply an inequality by a negative value, you change the direction of the inequality. So, the correct answer is r≤4
1. Distribute the -3 to the terms inside the parentheses:
-3r + 12 ≥ 0
2. Rearrange the inequality by subtracting 12 from both sides:
-3r ≥ -12
3. Divide both sides of the inequality by -3. Remember to reverse the inequality symbol when dividing by a negative number:
r ≤ 4
So, the solution to the inequality is r ≤ 4.