Find the force of attraction b/w two equal but opposite charge of 2*10micro, if the distance between them is 25cm
Find the force of attraction between two equal but opposite charges, of 2x10 C if the distance between them is 25 cm.
Find the force of attraction between two equal bars opposite changes of 2.0microcoulomb if the distance between them is 25cm
I need an answer
Answer
Q= 2 × 10^-6C
r= 0.25m
F= kQ²/r²
F= (9 × 10^-9) (2×10^-6)²/ (0.25)²
F= 0.576N
I need the Calculation
Q= 2 × 10^-6C
r= 0.25m
F= kQ²/r²
F= (9 × 10^-9) (2×10^-6)²/ (0.25)²
F= 0.576N