P varies partly as q and partly as the square of r. When p=6,q=8 r=4 and when p=10,q=12 and r=5. find the formula connecting p,q and r
p = mq + nr^2
so,
8m + 16n = 6
12m + 25n = 10
Now just solve for m,n
I don't understand the explanation
I don't understand
I understand not
So what is M and N now
I understand well
To find the formula connecting p, q, and r, we need to determine how p varies with q and r. Let's start by setting up the equation.
According to the problem statement, p varies partly as q and partly as the square of r. This can be represented as:
p = k * q * r^2
Where k is the constant of variation that we need to find.
Now let's use the first set of values given, where p=6, q=8, and r=4, to solve for k.
6 = k * 8 * 4^2
6 = 32k
Dividing both sides of the equation by 32, we get:
k = 6/32
k = 3/16
Now we have the value of k. Let's substitute it into the equation and use the second set of values given, where p=10, q=12, and r=5, to verify:
10 = (3/16) * 12 * 5^2
10 = (3/16) * 12 * 25
10 = 9 * 25
10 = 225
The equation checks out with the second set of values as well.
Therefore, the formula connecting p, q, and r is:
p = (3/16) * q * r^2