Given four distinct points neither three of which are collinear, how many planes are determined by these points?
A. One B. Three C. Three or one D. Four or one
Given three distinct lines such that each two of them are intersecting, how many planes are determined by these lines?
A. One B. Two C. Three or one D. Four or Three
The common points of two distinct planes are:
A. Two B. Three C. Infinitely many D. Infinitely many or none
What are your thoughts on the answers?
A, C, D, C
To determine the number of planes determined by four distinct points, we can use the formula:
Number of planes = nC3
where n represents the number of distinct points.
In this case, n = 4, so substituting the value:
Number of planes = 4C3 = 4! / (3! * (4-3)!) = 4
Therefore, the correct answer is D. Four or one.
Which of the following sets cannot determine uniquely a plane?
A. Three distinct non-collinear points
B. Line and a point that belongs to the line
C. Two parallel lines
D. Two intersecting lines
ACDC is a Great Band : )
The C's are both correct.
Please check your answers to #1 which you have "A"
and #3 which you chose "D"