A ship on the ocean surface detecte a sunken ship on the ocean floor at an angle of depression of 50 degrees . The distance between the ship on the surface and the sunken ship on the ocean floor is 200 meters . if the ocean floor is level in this are , how far above the ocean floor , to the nearest meter is the shop on the surface .
Tan50 = h/200.
h = 200*Tan50 =
h = 200 * sin(50º)
To find the distance above the ocean floor, we can use trigonometry and the given information. The angle of depression is the angle between the horizontal line (ocean floor) and the line of sight from the ship on the surface to the sunken ship. The opposite side of this angle is the distance above the ocean floor, and the adjacent side is the distance between the two ships.
Let's label the distance above the ocean floor as "x."
Using trigonometry, we can use the tangent function:
tan(50°) = x / 200m
Rearranging the equation to solve for x:
x = 200m * tan(50°)
Now, let's calculate the value of x approximately:
x ≈ 200m * tan(50°)
x ≈ 200m * 1.1918
x ≈ 238.36m
Thus, the ship on the surface is approximately 238 meters above the ocean floor. Remember to always round the answer to the nearest meter, so the final answer is approximately 238 meters.
henry2
if the distance between the two ships is 200 m
... how can the depth be greater than that?