The space shuttle releases a space telescope into orbit around the earth.the telescope goes from being stationary to traveling at a speed of 1700 m/s in 25seconds.what is the acceleration of the satellite?
To calculate the acceleration of the satellite, we can use the formula:
acceleration (a) = change in velocity (Δv) / time (t)
Given:
Initial velocity (u) = 0 m/s (as the telescope is initially stationary)
Final velocity (v) = 1700 m/s
Time (t) = 25 seconds
We can substitute these values into the formula:
a = (v - u) / t
a = (1700 m/s - 0 m/s) / 25 s
a = 1700 m/s / 25 s
a ≈ 68 m/s²
Therefore, the acceleration of the satellite is approximately 68 m/s².
To find the acceleration (a) of the satellite, we can use the formula:
acceleration (a) = change in velocity (Δv) / time taken (Δt)
Given:
Initial velocity (u) = 0 m/s (as the telescope is stationary initially)
Final velocity (v) = 1700 m/s
Time taken (Δt) = 25 seconds
We can calculate the change in velocity (Δv) using the formula:
change in velocity (Δv) = final velocity (v) - initial velocity (u)
Substituting the given values:
Δv = 1700 m/s - 0 m/s
Δv = 1700 m/s
Now, we can substitute the values of Δv and Δt into the acceleration formula to find the value of acceleration (a):
a = Δv / Δt
a = 1700 m/s / 25 s
a = 68 m/s²
Therefore, the acceleration of the satellite is 68 m/s².