m varies as (d+3).If m=28 when d=1, calculate:

a)the value of m, when d=3
b)the value of d, when m=49

a)M=k(d+3)

28=k(1+3)
28/4=7
7=k
M=7(3+3)
M=42
b)we know that k is 7 so,
49=7(d+3)
49/7=7
7-3=4
4=d

m = k(d+3)

So, m/(d+3) = k, a constant.

a) find m such that m/(3+3) = 28/4
b) find d such that 49/(d+3) = 28/4

a) Ah, this is a tricky one! To find the value of m when d=3, let's use our clown calculator and plug in the values. We know that m varies as (d+3), so we have m = (d+3).

When d=1, we are given that m=28. Let's substitute that into our equation and solve for the unknown:

28 = (1 + 3)
28 = 4

So, m = 4 when d = 1.

Now, to find the value of m when d = 3, we substitute d=3 into our equation:

m = (3 + 3)
m = 6

Therefore, when d=3, the value of m is 6.

b) Now, let's put on our clown glasses and calculate the value of d when m=49. We know that m varies as (d+3), so we have m = (d+3).

Simply substitute m=49 into the equation:

49 = (d + 3)

To isolate d, we subtract 3 from both sides:

49 - 3 = d
46 = d

So, when m = 49, the value of d is 46.

I hope my clownish calculations have brightened your day!

To find the value of m when d=3, we need to use the information given that m varies as (d+3).

Let's first find the constant of variation.

m = k (d+3)

We can substitute the given values m=28 and d=1 to find the value of k.

28 = k (1+3)
28 = k * 4
k = 7

Now that we have the constant of variation, we can find the value of m when d=3.

m = k (d+3)
m = 7 (3+3)
m = 7 * 6
m = 42

Therefore, the value of m when d=3 is 42.

To find the value of d when m=49, we can rearrange the equation as follows:

m = k (d+3)

Now, substitute m=49 and solve for d.

49 = 7 (d+3)
49 = 7d + 21
28 = 7d
d = 4

Therefore, the value of d when m=49 is 4.

Could somebody explain more in depth

I still do not understand the question