Which table of ordered pairs, when plotted, will form a straight line? Select two answers.
A.
x y
−2 −1
−1 0
0 1
5 6
B.
x y
−2 7
0 −3
3 12
5 22
C.
x y
−4 −3
0 5
2 9
5 12
D.
x y
−2 −8
0 −4
4 4
6 8
google demos graphing calculator!!!!
Does anyone know the answer?
B.
x y
−2 7
0 −3
3 12
5 22
D.
x y
−2 −8
0 −4
4 4
6 8
Because they satisfy the equation y = mx + b, where m is the slope and b is the y-intercept, and the points in both tables fall in a straight line pattern. But even though they form straight lines, remember that they won't be doing any stand-up comedy!
To determine which table of ordered pairs will form a straight line when plotted, we need to check if the slope between any two points is constant.
For option A, let's calculate the slope between each pair of points:
The slope between (-2, -1) and (-1, 0) is (0 - (-1))/(-1 - (-2)) = 1.
The slope between (-1, 0) and (0, 1) is (1 - 0)/(0 - (-1)) = 1.
The slope between (0, 1) and (5, 6) is (6 - 1)/(5 - 0) = 1.
The slopes between all pairs of points in option A are equal to 1, indicating that all the points lie on a straight line.
Now let's check the other options:
For option B:
The slope between (-2, 7) and (0, -3) is (-3 - 7)/(0 - (-2)) = -5.
The slope between (0, -3) and (3, 12) is (12 - (-3))/(3 - 0) = 5.
The slopes are not equal, so the points in option B do not form a straight line.
For option C:
The slope between (-4, -3) and (0, 5) is (5 - (-3))/(0 - (-4)) = 2.
The slope between (0, 5) and (2, 9) is (9 - 5)/(2 - 0) = 2.
The slope between (2, 9) and (5, 12) is (12 - 9)/(5 - 2) = 1.
The slopes are not equal, so the points in option C do not form a straight line.
For option D:
The slope between (-2, -8) and (0, -4) is (-4 - (-8))/(0 - (-2)) = 2.
The slope between (0, -4) and (4, 4) is (4 - (-4))/(4 - 0) = 2.
The slope between (4, 4) and (6, 8) is (8 - 4)/(6 - 4) = 2.
The slopes are equal, so the points in option D form a straight line.
So the correct answers are A and D.
I think the best way would be to get a sheet of graph paper and
actually do the plotting.