What is the valence electrons in V3+ have l=1 in quantum numbers?
To determine the valence electrons in V3+ with l=1 in quantum numbers, we need to look at the electron configuration of the V3+ ion.
First, let's start with the electron configuration of neutral vanadium (V). In its ground state, it has the electron configuration [Ar] 3d3 4s2.
Now, let's consider the V3+ ion, which has lost three electrons. To determine the electron configuration of V3+, we remove three electrons from the outermost shell, starting with the 4s electrons. Therefore, the electron configuration of V3+ would be [Ar] 3d0.
To determine the valence electrons with the given l value of 1, we need to understand that l represents the azimuthal quantum number or the sublevel. In this case, l=1 indicates the p sublevel.
From the electron configuration, we can see that there are no electrons present in the p sublevel (l=1) of the V3+ ion (3d0 configuration). Therefore, there are no valence electrons in V3+ with l=1.
So, to summarize, the valence electrons in V3+ with l=1 have a count of zero.