Y varies directly as the square of x and y=96 when x=4 find the value of y when x=5
How do I find the answers
varies directly: y = kx^2
That means that y/x^2 = k, a constant.
So, you want y such that
y/5^2 = 96/4^2
That means that y/x^2 = k, a constant.
So, you want y such that
y/5^2 = 96/4^2