Simplify; ( 3x^2 - 2x - 1) x 3root of 9x2 + 6x +1 / root of (x -1)^-1 × 6 root of (3x + 1)
Interpretation of this mess:
(3x^2 - 2x - 1)(3√(9x2 + 6x +1)) / (√( (x -1)^-1)(6√(3x + 1) )
= (3x+1)(x-1)3√(3x+1)^2 / ( (6√(3x+1)/(x-1))
= 3(3x+1)(x-1)(3x+1)(x-1) / (6√(3x+1))
= 3(3x+1)^2 (x-1)^2 / (6√(3x+1)) * √(3x+1)/√(3x+1)
= 3(3x+1)^2 (x-1)^2 * √(3x+1) / (6(3x+1))
= 3(3x+1)^(3/2) (x-1) / 6
= (3x+1)^(3/2) (x-1)^2 / 2
If you meant something else, make the necessary changes