Graph the following lines and write the equation in slope-intercept form.
Through the point (−8,1) with a slope of 3.
(-8, 1), m = 3.
Y = mx + b.
m = 3.
b = y - mx = 1 - 3*(-8) = 25.
the point-slope form is
y-1 = 3(x+8)
Now just rearrange it as needed.
What do you mean
To graph the line with a slope of 3 and passing through the point (-8, 1), we can use the slope-intercept form of a linear equation, which is given by:
y = mx + b
where "m" represents the slope and "b" represents the y-intercept.
Since we already know the slope is 3, we can substitute this value into the equation:
y = 3x + b
To find the value of "b", we substitute the coordinates of the given point (-8, 1) into the equation and solve for "b".
1 = 3 * (-8) + b
1 = -24 + b
To isolate "b", we add 24 to both sides of the equation:
1 + 24 = -24 + b + 24
25 = b
Therefore, the equation of the line in slope-intercept form is:
y = 3x + 25
To graph the line, we plot the given point (-8, 1) and then use the slope of 3 to determine additional points on the line.
Starting from the point (-8, 1), we move 1 unit up and 3 units to the right to reach the next point. We can repeat this process to find more points if needed.
After plotting the points, we can connect them to form a straight line. The resulting graph should show a line passing through the point (-8, 1) with a slope of 3.