calculate the number of moles of magnezium chloride produced by reacting 168kg of magnesium trioxocarbonate (iv) with excess hydrochloric acid
To calculate the number of moles of magnesium chloride produced, we need to use the molar ratio from the balanced chemical equation for the reaction between magnesium trioxocarbonate (MgCO3) and hydrochloric acid (HCl).
The balanced equation for the reaction is:
MgCO3 + 2HCl -> MgCl2 + CO2 + H2O
From the balanced equation, we can see that one mole of MgCO3 reacts with two moles of HCl to produce one mole of MgCl2.
First, let's calculate the number of moles of MgCO3:
First, convert the given mass of MgCO3 (168 kg) to grams:
168 kg * 1000 g/kg = 168,000 g
Next, calculate the number of moles of MgCO3 using the molar mass of MgCO3 (molar mass of Mg = 24.31 g/mol, molar mass of C = 12.01 g/mol, molar mass of O = 16.00 g/mol):
Molar mass of MgCO3 = 24.31 + 12.01 + (3 * 16.00) = 84.31 g/mol
Number of moles of MgCO3 = Mass of MgCO3 / Molar mass of MgCO3
= 168,000 g / 84.31 g/mol
Now, calculate the number of moles of MgCO3.
Now, let's use the molar ratio from the balanced equation to find the number of moles of MgCl2 produced.
From the balanced equation, we know that one mole of MgCO3 reacts to produce one mole of MgCl2.
Therefore, the number of moles of MgCl2 produced is the same as the number of moles of MgCO3, which we calculated earlier.
Hence, the number of moles of magnesium chloride produced by reacting 168 kg of magnesium trioxocarbonate (IV) with excess hydrochloric acid is calculated as follows:
Number of moles of MgCl2 = Number of moles of MgCO3
= 168,000 g / 84.31 g/mol