A box is pushed across a horizontal table by a boy applying a force of 32 N to the box. A force of friction of magnitude 19 N acts opposite the direction of motion. A stiff wind also opposes the box’s motion. What magnitude of force does the box exert on the boy’s hand?
To find the magnitude of the force exerted by the box on the boy's hand, we need to consider the forces acting on the box.
The forces acting on the box are:
1. The force applied by the boy (32 N) in the direction of motion.
2. The force of friction (19 N) acting opposite the direction of motion.
3. The force of the wind opposing the box's motion.
Since the box is being pushed in the direction of motion by the boy, the force exerted by the box on the boy's hand will be equal in magnitude but opposite in direction to the force applied by the boy.
Therefore, the magnitude of the force exerted by the box on the boy's hand is also 32 N.