Nitrogen Gas Occupy A Volume Of 413 At Pressure Of 217 Mmhg Caluclate Its New Volume When The Volume Increases To 612 Mmhg
assuming the temperature does not change, PV is constant.
So, you want V such that
V*612 = 413 * 217
and that's mmHg, not Mmhg
AND it's the new pressure you want. Volume is not measured in mm Hg.
yes, maybe. Since he said mmHg, I assumed he meant the new pressure instead of the new volume was 612 mmHg.
To solve this problem, we can use Boyle's Law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume.
Boyle's Law equation:
P1 * V1 = P2 * V2
Given:
Initial pressure (P1) = 217 mmHg
Initial volume (V1) = 413
Final pressure (P2) = 612 mmHg
Let's plug in the values we have:
P1 * V1 = P2 * V2
217 mmHg * 413 = 612 mmHg * V2
Now, we can solve for the new volume (V2):
V2 = (P1 * V1) / P2
V2 = (217 mmHg * 413) / 612 mmHg
V2 ≈ 146.46
Therefore, the new volume when the pressure increases to 612 mmHg is approximately 146.46.