A 2-member committee wil, be selected from 6 members of high school student council to attend a rally in Washington, D.C. How many dfferent 2- member committees are possible?
C(6,2) = 6!/(4!2!) = 15
Well, if we assume that all members of the student council have a strong desire to attend this exciting rally in Washington, D.C., we can calculate the number of possible 2-member committees using a little mathematical clown magic!
Since we're selecting 2 members from a total of 6, we can use the combination formula, known as "n choose r." In this case, n is the total number of members (6) and r is the number of members we want to select (2). So, let me juggle some numbers for you:
6 choose 2 = (6!) / (2! * (6-2)!)
= (6 * 5 * 4 * 3 * 2 * 1) / ((2 * 1) * (4 * 3 * 2 * 1))
= (720) / (4 * 24)
= (720) / (96)
= 7.5
Wait a minute, clowns can't deal with fractions! So we have to drop the ".5" because we can't have half members floating around!
Therefore, there are 7 different 2-member committees possible. So, students, put on your rally caps and get ready for a great time in Washington, D.C.!
To find the number of different 2-member committees possible, we can use the combination formula.
The formula for finding the number of combinations is given by:
C(n, r) = n! / ((n-r)! * r!)
Where n is the total number of items and r is the number of items chosen at a time.
In this case, there are 6 members and we need to select 2 members at a time. So, n = 6 and r = 2.
Using the combination formula, we can calculate the number of different 2-member committees possible:
C(6, 2) = 6! / ((6-2)! * 2!)
= 6! / (4! * 2!)
= (6 * 5 * 4!) / (4! * 2 * 1)
= (6 * 5) / (2 * 1)
= 30 / 2
= 15
Therefore, there are 15 different 2-member committees possible from the 6 members of the high school student council.
To find the number of different 2-member committees that can be selected from a group of 6 members, you can use the concept of combinations. The formula for combinations is given by:
C(n, r) = n! / (r! * (n - r)!)
Where n is the total number of items in the group, and r is the number of items to be selected.
In this case, n = 6 (as there are 6 members) and r = 2 (as we need to select 2 members for the committee).
Plugging in the values, we get:
C(6, 2) = 6! / (2! * (6 - 2)!)
= (6 * 5 * 4 * 3 * 2 * 1) / ((2 * 1) * (4 * 3 * 2 * 1))
= (720) / (4 * 6)
= 720 / 24
= 30
Therefore, there are 30 different 2-member committees possible from the 6 members of the high school student council.