You have 53 g of aluminum at25 degrees C.
How much heat must be added to raise its
temperature to 139 degrees C? Assume the specific
heat of aluminum is 903 J/kg · degrees C.
Answer in units of J
never mine y'all don't even help GN
Be patient.
q =mass in kg x specific heat in J/kg x (Tfinal-Tinitial)
q = 0.053 kg x 903 J/kg x (139-25) = ? J
To find the amount of heat required to raise the temperature of aluminum, you can use the formula:
Q = mcΔT
Where:
Q is the amount of heat
m is the mass of aluminum
c is the specific heat of aluminum
ΔT is the change in temperature
Let's plug in the values given in the question:
m = 53 g = 0.053 kg (since 1 kg = 1000 g)
c = 903 J/kg · °C
ΔT = 139 °C - 25 °C = 114 °C
Now, we can calculate the amount of heat using the formula:
Q = (0.053 kg)(903 J/kg · °C)(114 °C)
Q ≈ 5401.172 J
Therefore, you would need to add approximately 5401 J of heat to raise the temperature of 53 g of aluminum from 25 °C to 139 °C.