If 40cm cube of the carbon dioxide were mixed with with 30cm cube of oxygen.
Calcatute the volume of carbon diode produced?
which reactant is in excess and by how much?
what was the total volume of the gaseous mixture at the end of the reaction.?
How can CO2 mix with O2 and make more CO2? No reaction.
To calculate the volume of carbon dioxide produced in the reaction, we need to understand the balanced chemical equation for the reaction between carbon dioxide (CO2) and oxygen (O2).
The balanced equation for the reaction is:
2CO2 + O2 -> 2CO2
From the equation, we can see that two molecules of CO2 react with one molecule of O2 to produce two molecules of CO2.
Now, let's calculate the volume of carbon dioxide produced:
Given:
Volume of carbon dioxide (CO2) = 40 cm^3
Volume of oxygen (O2) = 30 cm^3
Since the volume of CO2 and O2 are given in cm^3, we can assume that the reaction occurs at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere pressure.
From the balanced equation, we can see that the ratio of CO2 to O2 is 2:1.
So, for every 2 volumes of CO2, we need 1 volume of O2.
Now, let's calculate the amount of CO2 produced.
Step 1: Determine the limiting reactant (the reactant that is entirely consumed first).
To do that, we need to compare the volumes of CO2 and O2.
Since 2 volumes of CO2 require 1 volume of O2, we can pair the volumes of CO2 and O2 as follows:
CO2 : O2
40 cm^3 : 30 cm^3
From the ratio, we can see that for every 40 cm^3 of CO2, we need 30 cm^3 of O2.
Step 2: Determine which reactant is in excess (the reactant that is leftover after the limiting reactant is consumed).
In this case, since 40 cm^3 of CO2 is required and 30 cm^3 of O2 is available, it means that O2 is the limiting reactant because we do not have enough O2 to react with all of the CO2.
Therefore, CO2 is in excess.
Step 3: Calculate the volume of CO2 produced.
Since O2 is the limiting reactant, it will be entirely consumed. Therefore, the reaction will depend on the amount of O2, and we can calculate the volume of CO2 produced based on the stoichiometry of the reaction.
From the equation, we know that for every 2 volumes of CO2 produced, 1 volume of O2 is consumed.
Since 1 volume of O2 is equal to 30 cm^3, we can calculate the volume of CO2 produced:
(2 volumes of CO2 / 1 volume of O2) * (30 cm^3) = 60 cm^3
So, the volume of carbon dioxide produced is 60 cm^3.
To determine the total volume of the gaseous mixture at the end of the reaction, we need to sum the volumes of CO2 and O2 before the reaction:
Total volume of gaseous mixture = Volume of CO2 + Volume of O2
Total volume of gaseous mixture = 40 cm^3 + 30 cm^3 = 70 cm^3
Therefore, the total volume of the gaseous mixture at the end of the reaction is 70 cm^3.
In summary:
- The volume of carbon dioxide produced is 60 cm^3.
- Oxygen (O2) is the limiting reactant.
- The excess amount of carbon dioxide (CO2) is 40 cm^3.
- The total volume of the gaseous mixture at the end of the reaction is 70 cm^3.