CALCULATE THE VOLUME OFHYDROGEN WHEN 25G OF ZINC ADDED TO HCL AT 31`C&778MMHG PRESSURE H=1,ZN=65,CL=35.5,<MOLAR VOLUME OF GAS AT STP=22.4DM>.
Zn +2 HCl >>>H2+ ZnCl2
so for every mole of zinc, one gets one mole of hydrogen gas. you have 25/65 moles of Zinc.
Use PV=nRT to solve for V
please help me to solve this question
To calculate the volume of hydrogen gas produced when 25g of zinc (Zn) is added to hydrochloric acid (HCl) at a temperature of 31°C and a pressure of 778 mmHg, you can follow these steps:
Step 1: Convert the mass of zinc (Zn) to moles.
- Determine the molar mass of zinc (Zn) from the periodic table. In this case, it is 65 g/mol.
- Use the formula: Moles = Mass / Molar mass.
- Moles of zinc = 25g / 65 g/mol.
Step 2: Write and balance the chemical equation.
The chemical equation for the reaction of zinc (Zn) with hydrochloric acid (HCl) is:
Zn + 2HCl → ZnCl₂ + H₂.
Step 3: Determine the stoichiometry of the reaction.
From the balanced equation, you can see that one mole of zinc (Zn) reacts to produce one mole of hydrogen gas (H₂).
Step 4: Convert moles of zinc to moles of hydrogen gas.
Since the reaction occurs in a 1:1 ratio, the moles of hydrogen gas will be the same as the moles of zinc.
Step 5: Calculate the volume of hydrogen gas.
To calculate the volume of hydrogen gas, we need to use the ideal gas law equation: PV = nRT.
- Convert the temperature from Celsius to Kelvin by adding 273.15.
- Plug in the values: P = 778 mmHg, T = 31°C + 273.15 = 304.15 K, V = ? (volume in liters), n = moles of hydrogen gas.
Step 6: Convert the volume to liters.
Since the molar volume of a gas at STP (Standard Temperature and Pressure) is given as 22.4 L/mol, you can use this value to convert the volume from liters to moles.
- Volume in liters = Moles of hydrogen gas * Molar volume at STP.
By following these steps, you can calculate the volume of hydrogen gas produced.