Compute the following:
Let g(x)=3x, and h(x)=x^2+1.
h(3)
Please show work & help me understand.
for any value of x, h(x)=x^2+1
so, replace x with 3 and you have
h(3) = 3^2+1
That’s all to it?
To find the value of h(3), you need to substitute 3 into the function h(x) and compute the result.
Given that h(x) = x^2 + 1, we substitute x with 3:
h(3) = 3^2 + 1
Now we can simplify the expression:
h(3) = 9 + 1
h(3) = 10
Therefore, h(3) = 10.