A solid weight 4.8g in air, 2.8g in water and 3.2 in kerosine calculate the relative density of the kerosine
show me how u solved it
first find the volume
It displaced 4.8 - 2.8 = 2 grams of water
water has density of 1 gram/ cm^3
so its volume is 2 cm^3
in kerosene it displaces the same volume = 2 cm^3
however that 2 cm^2 weighs
4.8 - 3.2 = 1.6 grams
so kerosene s 1.6 grams / 2 cm^3 = 0.8 grams/cm^3 or 0.8 times water density
To calculate the relative density of the kerosene, we need to compare its density with the density of water. The formula for relative density is:
Relative Density = Density of Substance / Density of Reference Substance
In this case, the density of water is our reference substance. We are given the weights of the solid in air, water, and kerosene, but we need to convert these weights to masses.
To convert the weights to masses, we use the formula:
Mass = Weight / Acceleration due to Gravity
Assuming the acceleration due to gravity is 9.8 m/s², we can calculate the masses of the solid in air, water, and kerosene.
Mass in air = 4.8g / 9.8 m/s² = 0.49 kg
Mass in water = 2.8g / 9.8 m/s² = 0.29 kg
Mass in kerosene = 3.2g / 9.8 m/s² = 0.33 kg
Now, we can calculate the density of kerosene using the formula:
Density = Mass / Volume
However, we don't have the volume of the solid in kerosene. But since the relative density is the ratio of densities, we can eliminate the volume from the equation. So we can calculate the density of kerosene using the masses alone.
Density of kerosene = Mass in kerosene / Volume in kerosene
Since the volume cancels out in the calculation, we can obtain the density of kerosene as:
Density of kerosene = Mass in kerosene / (Mass in air - Mass in water)
Density of kerosene = 0.33 kg / (0.49 kg - 0.29 kg)
Density of kerosene = 0.33 kg / 0.20 kg
Density of kerosene = 1.65 kg
Therefore, the relative density of kerosene is 1.65.