3.the total amount Jurene paid for 5 kilos of rice and 2 kilos of fish is less than php 600
a.what mathematical statement represents the total amount Jurene paid?Define the variables used.
b.suppose a kilo of rice costs php 35.what could be the greatest cost of a kilo of fish to the nearest pesos?
c.suppose Jurene paid more than php 600 and each kilo of rice costs php 34.what could be the least amount she will oay for 2 kilos of fish to the nearest pesos?
Let the cost per kg of rice be r
let the cost per kg of fish be f
5r + 2f < 600
b) let r = 35, then
5(35) + 2f < 600
2f < 425
f < 212.5
c) let r = 34
5(34) + 2f > 600
take over
What is the answer of c?
What the answer
what is the of c
need answer
Answer pla
A kilo of rice cost php 40 8.50 point about how much will 5 kilo costs
A kilo of rice cost php 48. About how much will 5 kilo costs
👍 11 👁️ 10000 🚩66
a. The mathematical statement that represents the total amount Jurene paid can be expressed as:
Total Cost = Cost of Rice + Cost of Fish
Let's define the variables used:
- Cost of Rice: denoted as R (in PHP)
- Cost of Fish: denoted as F (in PHP)
- Total Cost: denoted as TC (in PHP)
So, the mathematical statement becomes:
TC = R + F
b. We know that the total amount Jurene paid for 5 kilos of rice and 2 kilos of fish is less than PHP 600. If a kilo of rice costs PHP 35, we can find the greatest possible cost of a kilo of fish to the nearest peso.
Given:
Cost of Rice (R) = PHP 35
Total Cost (TC) < PHP 600
We can substitute the values into the mathematical statement:
TC = R + F
TC < 600
35 + F < 600
Now, we can isolate F by subtracting 35 from both sides:
F < 565
So, the greatest possible cost of a kilo of fish to the nearest peso is PHP 565.
c. Suppose Jurene paid more than PHP 600 and each kilo of rice costs PHP 34. We need to find the least amount she will pay for 2 kilos of fish to the nearest peso.
Given:
Cost of Rice (R) = PHP 34
Total Cost (TC) > PHP 600
Quantity of Fish (Q) = 2
We can substitute the values into the mathematical statement:
TC = R + F
TC > 600
34 + F > 600
Now, we can isolate F by subtracting 34 from both sides:
F > 566
So, the least amount Jurene will pay for 2 kilos of fish to the nearest peso is PHP 566.