The number f of miles a helicopter is from its destination x minutes after takeoff is given by f(x)=75−1.5x. The number f of miles a commercial jet is from its destination x minutes after takeoff is shown in the graph below. The graph has f(x) at 600 miles and the x is 100 minutes. Need to find: the helicopter travelled ? in ? minutes and the commercial jet travelled ? in ? minutes.
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To find the distance traveled by the helicopter and the commercial jet, we need to look at the given equation for the helicopter's distance and the graph for the jet's distance.
1. Helicopter: The equation given for the helicopter's distance is f(x) = 75 - 1.5x.
- We need to find the distance traveled and the time taken.
- Substitute the time value x = ? minutes into the equation to find the distance traveled by the helicopter.
2. Commercial Jet: The graph shows the distance (f) on the y-axis and time (x) on the x-axis. You mentioned that the graph has f(x) at 600 miles and x at 100 minutes.
- We need to find the time taken and the distance traveled by the commercial jet.
- On the graph, locate the point where f(x) = 600 miles (y-axis) and x = 100 minutes (x-axis).
- Read the corresponding value on the y-axis to find the distance traveled by the commercial jet.
- Read the corresponding value on the x-axis to find the time taken.
Please provide the values for x and y for the helicopter's distance equation and the values for the graph to proceed with the calculations.